document updated 16 years ago, on Dec 19, 2007

### Range

To determine the min and max possible values for dice tosses such as `2d3+3`, simply take the
lowest (or highest) value on **one** die toss, and run it through the equation. So:
`min = 2*`**1** + 3 = 5
`max = 2*`**3** + 3 = 9

### Expected value

As far as I can tell, the expected value is always the midpoint of the range. So that's easy, it's just `(min+max)/2`. For the above, that'd be (5+9)/2 = 14/2 = 7.
### Resources

If you're doing complicated things, Games::Dice::Probability is useful. This is a friendly wrapper around it. I've used it to double-check the above though, so perhaps just stick with the easier method...